Disclaimer
I am going to propose something both fun and at same time, has a large potential to be controversial. If you want me to make a video on it, to explain thoughts more detail, let me know. With the disclaimer out of the way.
Basics of Mechanic
The basic principle of this system is how TWO different systems will be working in conjunction: System One: works for [CoF] [merchants Guild], System Two: Works for targeting one specific item that you want.
System One
When you join a guild, regardless of which faction, you will unlock a reward matrix track. Like in GW2, where you do pvp you fill a bar, fill the bar enough you are given a chest with a small reward, and the rewards increase the further down the track you progress.
This rewards are DETERMINISTIC. YOU ARE GUARANTEED THE ITEM, AND THE LP as you pick from a large drop table, and it SPAWNS THE ITEM.
LET:
E= EXP CAP for Tier = 100%
N= Result = 100%, aka gear drops at 1 = 100%
K = Kills
C= Corruption
P= 1 + K
Nx = The chain of boxes, N2 would be 2nd box
PR= Value of a monster for a Kill [ PR= {C+ P} + C/N*x]
[CoF/ Merchants]: Unlocks at Tier 10 [legacy] or tier 6 [cycle] or tier 4 [hardcore]. For a âBOXâ you would need to unlock 10 small crates. Exp requirements for each boxes = N*x
N1=> 0+ [[ PR * [C+K] / [E+N*x]
N2= N1 squared
N3= N2 squared
N4= N3 Squared
N10= N9 Squared
The numbers are a little complicated, but the idea is that the harder the enemy you fight, and the less the enemies are spawned on the map, the more the value of the enemy is: the devs would need to add a number like CR in DnD for each monster. This way, when you fight a boss, the Bosses PR=100%
In practice unlocking the 10th box is almost impossible. The exp required is in the trillions. How ever, if you wanted to play the game for 40 years offline, you would be able to hit N10
Getting a Tier N7 is doable however, for those who want to play the game like its their job, and also allows casuals to get decent 2LP uniques a lot easier.
System 2
This system is different, it allows you to pick 1 item to drop, for every X bosses you can clear. It is more practical for most people, as it seems most people in LE hate boss farming.
Let C= Corruption / 10 [Result number is rounded down to closest number]
Let N = Value needed to hit the âValueâ on a spreadsheet to trigger a tier
Let T= Total kills needed for a tier
Tier 1= 10 kills + score for kill = 1 [corruption= 100]
Tier 2= 20 âŚ
Tier 3= 30 âŚ
Tier 4= 50 âŚ
Tier 5= 70 ⌠Score of 50 [corruption 500]
Tier 6= 85 âŚ
Tier 7= 100 ,âŚ
Tier 10= 150 and Score of 100 [corruption= 1000]
The Maximum = N= 1000 [highest corruption cleared] / 10 = 100
This system is designed to be fair without being excessive, altough i think some may find that clearing 150 bosses on corruption 1000 to maybe to much. But i think its fair for a stretch goal.
Do you agree? What would you change? If you have a better formula, please share it. Math is not my specialty, so maybe one here can do a better job.
EDIT: would not display equation correctly.